document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251090>Question 251090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 30y to the fourth power divided by -5y to the second power<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182823 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 30y to the fourth power divided by -5y to the second power\r<BR>\n" );
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document.write( "We have 30y^4/-5y so:\r<BR>\n" );
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document.write( "30y^4/-5y = (30/-5)*(y^4)*(y^(-1)) = -6*y^(4-1) = -6*y^3 </SPAN>\n" );
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