document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31446>Question 31446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3) A regular hexagon is inscribed in a circle with circumference of 16&#960;. A second circle is inscribed inside the hexagon.  If you pick a point at random inside the larger circle, what is the probability that the point is also in the area of the smaller circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18274 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CIRCUMFERENCE OF OUTER CIRCLE =16*PI<BR>\n" );
document.write( "DIAMETER=16*PI/PI=16...........RADIUS =8<BR>\n" );
document.write( "AREA=8*8*PI=64*PI<BR>\n" );
document.write( "INSCRIBED CIRCLE WILL HAVE ITS RADIUS EQUAL TO ALTITUDE OF ANY EQUILATERAL  TRIANGLE FORMED BY ONE SIDE OF HEXAGON WITH CENTRE OF BIG CIRCLE.<BR>\n" );
document.write( "SIDE OF HEXAGON = RADIUS OF CIRCUM CIRCLE =8<BR>\n" );
document.write( "ALTITUDE = 8 *SIN60=8*SQRT.(3)/2=4SQRT.3<BR>\n" );
document.write( "SO AREA OF INNER CIRCLE=PI*4*4*(SQRT.3)^2=48*PI<BR>\n" );
document.write( "SO PROBBILITY OF A RANDOM POINT SELECTED IN BIG CIRCLE WILL FALL IN THE SMALLER CIRCLE=AREA OF SMALL CIRCLE/AREA OF BIG CIRCLE= 48*PI/64*PI=3/4=0.75 </SPAN>\n" );
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