document.write( "Question 250872: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
\n" ); document.write( "A rectangular window is 10 inches longer than it is wide. If the area of the window is 1200 square inches, find the length and the width.
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Algebra.Com's Answer #182733 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve using the five-step problem-solving process.
\n" ); document.write( " Show all steps necessary to arrive at your solution.
\n" ); document.write( "A rectangular window is 10 inches longer than it is wide.
\n" ); document.write( " If the area of the window is 1200 square inches, find the length and the width.
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\n" ); document.write( "Let x = the width of the window
\n" ); document.write( "then
\n" ); document.write( "(x+10) = the length
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\n" ); document.write( "Area: L * W, therefore
\n" ); document.write( "x(x+10) = 1200
\n" ); document.write( "x^2 + 10x = 1200
\n" ); document.write( "x^2 + 10x - 1200 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(x + 40)(x-30) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = 30 inches is the width
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\n" ); document.write( "The width is 30\" and the length is 10\" more, 40\"
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\n" ); document.write( "Check by finding the area: 30 * 40 = 1200 sq/in
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