document.write( "Question 31493: Eighteen guests have to be seated,half on each side of a long table.If four particular guests desire to sit on one
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document.write( "particular side and three others on the other side,the number of ways in which the sitting arrangement can be made is
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document.write( "A.11C5*9!*9!
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document.write( "B.11C6*8!*10!
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document.write( "C.11C5*8!*10!
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document.write( "D.None of the above \n" );
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Algebra.Com's Answer #18272 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! 9 ARE TO BE ON 1 SIDE.4 ARE ALREADY ON ONE SIDE AND 3 ON OTHER SIDE. \n" ); document.write( "THERE ARE 11 LEFT. \n" ); document.write( "WE CAN SELECT 5 OF THEM IN 11C5 WAYS TO SIT ALONG WITH 4.\r \n" ); document.write( "\n" ); document.write( "REST WILL AUTOMATICALLY GO TO OTHER SIDE.THIS CAN BE DONE IN ONLY 1 WAY . \n" ); document.write( "NOW 9 ON EITHER SIDE CAN BE ARRANGED IN 9! WAYS...SO THE TOTAL NUMBER OF ARRANGEMENTS ARE \n" ); document.write( "11C5*9!*9!.....A IS THE ANSWER \n" ); document.write( " |