document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250847>Question 250847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Just a random question: \"Originally a rectangle was twice as long as it was wide.  When 4 m were added to its length and 3 m subtracted from its width, the resulting rectangle had an area of 600 m (squared).  Find the dimensions of the new rectangle.\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182677 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x + 4) (w - 3) = 600\r<BR>\n" );
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document.write( "2w^2 - 2w - 612 = 0 ___ w^2 - w - 306 = 0\r<BR>\n" );
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document.write( "(w + 17) (w - 18) = 0 ___ w = 18\r<BR>\n" );
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document.write( "L = 2w + 4 = 40\r<BR>\n" );
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document.write( "W = w - 3 = 15 </SPAN>\n" );
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