document.write( "Question 250740: Find four consecutive multiples of five such that twice the sum of the two biggest exceeds twice the smallest by ten. \n" ); document.write( "

Algebra.Com's Answer #182646 by Edwin McCravy(20055) $\"\"$ $\"About$

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Find four consecutive multiples of five such that twice the sum of the two biggest exceeds twice the smallest by ten.
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document.write( "5k     = smallest multiple of 5\r\n" );
document.write( "5(k+1) = next to smallest multiple of 5\r\n" );
document.write( "5(k+2) = next to biggest multiple of 5\r\n" );
document.write( "5(k+3) = biggest multiple of 5\r\n" );
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document.write( ">>twice the sum of the two biggest... \r\n" );
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document.write( "sum of the two biggest = 5(k+2) + 5(k+3)\r\n" );
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document.write( "twice the sum of the two biggest = 2[5(k+2) + 5(k+3)]\r\n" );
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document.write( "...exceeds twice the smallest by ten.<<\r\n" );
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document.write( "twice the smallest = 2(5k)\r\n" );
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document.write( "2[5(k+2) + 5(k+3)] = 2(5k) + 10\r\n" );
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document.write( "Can you solve that for k?  If not post again asking how.\r\n" );
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document.write( "Solution: k = -4\r\n" );
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document.write( "smallest multiple of 5         = 5k     = 5(-4)   =         -20\r\n" );
document.write( "next to smallest multiple of 5 = 5(k+1) = 5(-4+1) = 5(-3) = -15\r\n" );
document.write( "next to biggest multiple of 5  = 5(k+2) = 5(-4+2) = 5(-2) = -10\r\n" );
document.write( "biggest multiple of 5          = 5(k+3) = 5(-4+3) = 5(-1) =  -5\r\n" );
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document.write( "So they are -20, -15, -10, -5.    \r\n" );
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document.write( "Edwin

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