document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250743>Question 250743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line that passes through the given point and is parallel to the given line. (5,4), y=3x+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182603 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First parallel lines have the same slope..so you know that \r<BR>\n" );
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document.write( "y = 3x + 5 has a slope of 3\r<BR>\n" );
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document.write( "then you have the point (5, 4)\r<BR>\n" );
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document.write( "so: the new equation would start as \r<BR>\n" );
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document.write( "4 = 3(5) + b...now solve for b\r<BR>\n" );
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document.write( "4 = 15 + b  subtract 15 from both sides<BR>\n" );
document.write( "-11 = b\r<BR>\n" );
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document.write( "so now we can write the equation\r<BR>\n" );
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document.write( "y = 3x - 11\r<BR>\n" );
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document.write( "Hope this helps<BR>\n" );
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