document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250707>Question 250707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what are the factors of x3+2x2-63x ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182600 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First factor out an x\r<BR>\n" );
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document.write( "so x^3 + 2x^2 - 63  would be:\r<BR>\n" );
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document.write( "(x)(x^2 + 2x - 63)  well, your best option is probably 7 x 9 = 63\r<BR>\n" );
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document.write( "so now you can factor the second part\r<BR>\n" );
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document.write( "(x)(x + 9)(x - 7)\r<BR>\n" );
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document.write( "hope this helps </SPAN>\n" );
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