document.write( "Question 250710: Can you explain how to do mixture formulas such as:
\n" ); document.write( "How many liters of 30% alcohol must be mixed with 20 liters of 80% alcohol to obtain a 50% alcohol solution?
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Algebra.Com's Answer #182577 by richwmiller(17219)\"\" \"About 
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http://www.purplemath.com/modules/mixture.htm
\n" ); document.write( "In this case
\n" ); document.write( ".30x+.80*20=.50(x+20)
\n" ); document.write( "The trick here is that we don't know the total amount of solution in the end.
\n" ); document.write( "But we do know how much 80 % solution there is.
\n" ); document.write( "So we will add x amount so the total will be (20 + x)
\n" ); document.write( "Solve the equation will give you x-- the amount of 30% to be added
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