document.write( "Question 249949: Write a system of equations that could be used to solve the following problem. express each of the systems in standard form. Use the inverse matrix method to solve with a calculator. Paula invested $6,500 in three different bank accounts for one year. One account earned 5% interest for the year, and the other two accounts earned 8% and 10% respectively. the total interest earned for the three investments was $560 for the year. If the sum of the 5% and 8% investments was $500 less than the 10% investment, find the amount invested in each account. \n" ); document.write( "
Algebra.Com's Answer #182573 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
I did NOT use the inverse matrix method but all the info and equations you need should be here.\r
\n" ); document.write( "\n" ); document.write( "I=Prt
\n" ); document.write( "P=6500
\n" ); document.write( "I=560
\n" ); document.write( "t=1
\n" ); document.write( "r1=5%
\n" ); document.write( "r2=8%
\n" ); document.write( "r3=10%
\n" ); document.write( "P1+P2=P3-500
\n" ); document.write( "6500=P3-500+P3
\n" ); document.write( "3500=P3
\n" ); document.write( "P1+P2=3000
\n" ); document.write( "I=Prt
\n" ); document.write( "I3=3500*.10*1=350
\n" ); document.write( "I1+I2=560-350=210\r
\n" ); document.write( "\n" ); document.write( ".05 (P1)+.08(3000-P1)=210
\n" ); document.write( "1000=P1
\n" ); document.write( "P2=3000-P1=2000
\n" ); document.write( "so we have
\n" ); document.write( "P1=1000
\n" ); document.write( "P2=2000
\n" ); document.write( "P3=3500
\n" ); document.write( "r1=5%
\n" ); document.write( "r2=8%
\n" ); document.write( "r3=10%
\n" ); document.write( "I1+I2=210
\n" ); document.write( "I3=350
\n" ); document.write( "I1 can be found by I=Prt
\n" ); document.write( "I2 can be found by I=Prt or 210-I1\r
\n" ); document.write( "
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