document.write( "Question 250676: Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, seperated by a coma. \r
\n" ); document.write( "\n" ); document.write( "A. drawing a black seven out of a standard 52 card deck given it's not a face card or an ace.\r
\n" ); document.write( "\n" ); document.write( "B. rolling a total of 4 on two fair six sided dice.\r
\n" ); document.write( "\n" ); document.write( "C. drawing a three out of a standard 52 card deck given it's not a face card or an ace.\r
\n" ); document.write( "\n" ); document.write( "D. rolling a total of 9 on two fair six sided dice.\r
\n" ); document.write( "\n" ); document.write( "E. rolling a total of 7 on two fair six sided dice.
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Algebra.Com's Answer #182559 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "There are 3 ways to make a 4, 4 ways to make a 9, and 6 ways to make a 7 rolling a pair of 6-sided dice. There are 36 total possibilities for the sum of two 6-sided dice.\r
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\n" ); document.write( "\n" ); document.write( "There are 3 face cards in each of 4 suits for a total of 12 face cards, plus there are 4 aces for a total of 16 excluded cards from the deck of 52. That leaves 52 - 16 equals 36 possible cards.\r
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\n" ); document.write( "\n" ); document.write( "A. There are 2 black 7s in the possible 36 cards. \r
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\n" ); document.write( "\n" ); document.write( "B. 3 ways to make a 4 out of 36: \r
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\n" ); document.write( "\n" ); document.write( "C. There are 4 threes in the possible 36 cards. \r
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\n" ); document.write( "\n" ); document.write( "D. 4 ways to make a 9 out of 36: \r
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\n" ); document.write( "\n" ); document.write( "E. 6 ways to make a 7 out of 36: \r
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