document.write( "Question 250559: I need help with my Algebra please. It says tell whether each sequence is convergent or divergent. If it is convergent find it sum.\r
\n" ); document.write( "\n" ); document.write( "1. infinite E (2/3)^n n=0\r
\n" ); document.write( "\n" ); document.write( "2. infinite E (-4/11)^n n=0\r
\n" ); document.write( "\n" ); document.write( "3. infinite E (5^k+1)/3^k n=0\r
\n" ); document.write( "\n" ); document.write( "4. infinite E (3^n-1)/4^n n=1
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Algebra.Com's Answer #182502 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: Recall that the series \"sum%28a%2Ar%5En%2Cn=0%2Cinfinity%29\" is convergent if \"abs%28r%29%3C1\" and it diverges otherwise. If it converges, then \"sum%28a%2Ar%5En%2Cn=0%2Cinfinity%29=a%2F%281-r%29\"\r
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\n" ); document.write( "\n" ); document.write( "So for the first problem, let \"a%2Ar%5En=%282%2F3%29%5En\" which makes \"a=1\" and \"r=2%2F3\". Because \"abs%28r%29=abs%282%2F3%29%3C1\", this means that \"sum%28%282%2F3%29%5En%2Cn=0%2Cinfinity%29=1%2F%281-2%2F3%29=1%2F%281%2F3%29=3\". Use the same idea for the rest of the problems.
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