document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250598>Question 250598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cruise boat travels 48 miles downstream in 3 hours and returns upstream in 6 hours. Find the rate of the stream. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182484 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rate*time=distance<BR>\n" );
document.write( "x*3=48<BR>\n" );
document.write( "x=16 with current\r<BR>\n" );
document.write( "\n" );
document.write( "y*6=48<BR>\n" );
document.write( "y=6 against current\r<BR>\n" );
document.write( "\n" );
document.write( "16-6=10 difference in speeds\r<BR>\n" );
document.write( "\n" );
document.write( "10/2=5 mph stream current<BR>\n" );
document.write( "5+11=16 with current<BR>\n" );
document.write( "11-5=6 against current<BR>\n" );
document.write( "11 mph with no current </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );