document.write( "Question 31564: Find the number of different 5-card hands that can be dealt from a standard deck of 52 playing cards?\r
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document.write( "Find the probability that 4 kings and a queen are randomly drawn from a standard deck of 52 playing cards? \n" );
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Algebra.Com's Answer #18245 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! ok....52 cards:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 52 possible choices...Pick one \n" ); document.write( "there are now 51... Pick second \n" ); document.write( "there are now 50... pick the third \n" ); document.write( "there are now 49... pick 4th \n" ); document.write( "there are now 48... pick 5th\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, possible number of variations are: 52*51*50*49*48. However, some of these are repeated. How many are repeated?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Well, look at an easier example: Pick 2 letters from ABCDE:\r \n" ); document.write( "\n" ); document.write( "AB BA CA DA EA \n" ); document.write( "AC BC CB DB EB \n" ); document.write( "AD BD CD DC EC \n" ); document.write( "AE BE CE DE ED\r \n" ); document.write( "\n" ); document.write( "So from 5 choices we have 5*4 --> 20. And yet AB is the same as BA, in terms of them being playing cards...the hand is the same irrespective of having A then B dealt or B then A...the hand is still \"A and B\". Looking, there are actually only 10 different \"hands\" in this example: 20/2!. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another example: pick 3 from the 5: \n" ); document.write( "ABC BCD CDE \n" ); document.write( "ABD BCE \n" ); document.write( "ABE BDE \n" ); document.write( "ACD \n" ); document.write( "ACE \n" ); document.write( "ADE\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here there are 10 solutions gotten from (5*4*3)/3!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, for your question, we get 52*51*50*49*48/5! \n" ); document.write( "which is 2,598,960 different hands\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This gives us that the probability of a particular hand = 1/2598960\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now P(4 kings and a queen) is actually 4 potential hands... \n" ); document.write( "4K and Q clubs or \n" ); document.write( "4K and Q diamonds or \n" ); document.write( "4K and Q hearts or \n" ); document.write( "4K and Q spades\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, P(4K and a Q) = 4*(1/2598960) \n" ); document.write( "4/2598960\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As you can see, the odds are very small of this happening\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |