document.write( "Question 250056: Working together, two pumps can drain a certain pool in 5 hours. If it takes the older pump 15 hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own? \n" ); document.write( "
Algebra.Com's Answer #182423 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Working together, two pumps can drain a certain pool in 5 hours. \n" ); document.write( " If it takes the older pump 15 hours to drain the pool by itself, \n" ); document.write( " how long will it take the newer pump to drain the pool on its own? \n" ); document.write( ": \n" ); document.write( "you can do this in your head but here is an algebra equation way \n" ); document.write( ": \n" ); document.write( "Let t = time required by new pump to drain the pool \n" ); document.write( ": \n" ); document.write( "Let the completed job (drained pool) = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by 15t \n" ); document.write( "t(5) + 15(5) = 15 \n" ); document.write( "5t + 75 = 15t \n" ); document.write( "75 = 15t - 5t \n" ); document.write( "75 = 10t \n" ); document.write( "t = 75/10 \n" ); document.write( "t = 7.5 hrs new pump alone \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( "5/15 + 5/7.5 = \n" ); document.write( ".33 + .67 = 1 \n" ); document.write( " \n" ); document.write( " |