document.write( "Question 250438: one roofer can put a new roof on a house three times faster than another. Working together, they can roof a house in 4 days. How long would it take the faster roofer working alone? \n" ); document.write( "
Algebra.Com's Answer #182337 by chosenpoint(26)\"\" \"About 
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Rate-of-work-word-problems/250438 (2009-12-15 21:54:41): one roofer can put a new roof on a house three times faster than another. Working together, they can roof a house in 4 days. How long would it take the faster roofer working alone?
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\n" ); document.write( "\n" ); document.write( "Let x be the fastest roofers time to roof the house
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\n" ); document.write( "\n" ); document.write( "Then the slower roofers time will be 3x
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\n" ); document.write( "\n" ); document.write( "Use the following formula to calculate how the work is done:
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\n" ); document.write( "\n" ); document.write( "\"1%2FA%2B1%2FB=1%2FC\" where A & B are the times done by themselves, and C is the time it takes them to do the work together, thus we have:
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx%2B1%2F3x=1%2F4\"
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\n" ); document.write( "\n" ); document.write( "\"3%2F3x%2B1%2F3x%2B1%2F4\"
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\n" ); document.write( "\n" ); document.write( "\"4%2F3x=1%2F4\"
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\n" ); document.write( "\n" ); document.write( "\"3x=16\"
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\n" ); document.write( "\n" ); document.write( "\"x=16%2F3\"
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\n" ); document.write( "\n" ); document.write( "So the fast roofer can do it by himself in about 5.33 days! Hope that helps! :)
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