document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250370>Question 250370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a beaker of a 3% acid solution and a beaker of a 7% acid solution.  He needs to make 75ml of a 4% acid solution.  complete the table.\r<BR>\n" );
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document.write( "a.<BR>\n" );
document.write( "                        3%solution + 7%solution = 4%solution<BR>\n" );
document.write( "amount of solution(ml)  ____x      + ______y    =       <BR>\n" );
document.write( "amount of acid (ml)     ____x      + ______y    = 0.04(75)\r<BR>\n" );
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document.write( "b. Use the informaiton in the table to write a system of linear equations.\r<BR>\n" );
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document.write( "c. Solve the system of equations to find how much he will use from each beaker. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182300 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">                         3%solution + 7%solution = 4%solution<BR>\n" );
document.write( "amount of solution(ml)  x + y = 75 OR x=75-y     <BR>\n" );
document.write( "amount of acid (ml)    .03x + .07y  = 0.04(75)<BR>\n" );
document.write( ".03(75-y)+.07y=3<BR>\n" );
document.write( "2.25-.03y+.07y=3<BR>\n" );
document.write( ".04y=3-2.25<BR>\n" );
document.write( ".04y=.75<BR>\n" );
document.write( "y=.75/.04<BR>\n" );
document.write( "y=18.75 ml of 7% solution is used.<BR>\n" );
document.write( "x+18.75=75<BR>\n" );
document.write( "x=75-18.75<BR>\n" );
document.write( "x=56.25 ml. of 3% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".03*56.25+.07*18.75=.04*75<BR>\n" );
document.write( "1.6875+1.3125=3<BR>\n" );
document.write( "3=3\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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