document.write( "Question 31586: Can I please get some help with this question?\r
\n" ); document.write( "\n" ); document.write( "Time on a treadmill. After 2 minutes on a treadmill Jenny has a heart rate of 82. After 3 mins she has a heart rate of 86. Assume that there is a linear equation that gives her heart rate h in terms of time on the tread mill t. Find the equation and use it to predict her heart rate after 10 mins on the treadmill. \n" ); document.write( "
Algebra.Com's Answer #18229 by venugopalramana(3286)\"\" \"About 
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Time on a treadmill. After 2 minutes on a treadmill Jenny has a heart rate of 82. After 3 mins she has a heart rate of 86. Assume that there is a linear equation that gives her heart rate h in terms of time on the tread mill t. Find the equation and use it to predict her heart rate after 10 mins on the treadmill.
\n" ); document.write( "AT T=2...H=82
\n" ); document.write( "AT T=3....H=86
\n" ); document.write( "INCREAE IN TIME =3-2=1
\n" ); document.write( "INCREASE IN HEART RATE IN THIS PERIOD = 86-82=4
\n" ); document.write( "RATE OF INCREASE PER UNIT TIME = 4/1=4
\n" ); document.write( "IN LINEAR RELATION THIS REMAINS CONSTANT.
\n" ); document.write( "SO TAKING BASE VALUE AS T=2 AND H=82..WE GET FOR ANT TIME T AND RATE H
\n" ); document.write( "INCREASE IN TIME =T-2
\n" ); document.write( "INCREASE IN RATE=H-82
\n" ); document.write( "RATE OF INCREASE =(H-82)/(T-2)=4
\n" ); document.write( "H-82=4(T-2)=4T-8
\n" ); document.write( "H-4T=82-8=74
\n" ); document.write( "SO THE EQN. IS
\n" ); document.write( "H-4T=74
\n" ); document.write( "HENCE AT T=10 WE GET
\n" ); document.write( "H=74+4*10=114 \n" ); document.write( "
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