document.write( "Question 250181: An ultra light aircraft flies to a nearby town that is 20 miles away in 2/5 hour with a tail wind. It can fly back home again when fighting a head wind in 1/2 hour. Find the air speed of the ultra light aircraft and the wind speed. \n" ); document.write( "
Algebra.Com's Answer #182243 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR R=D/T \n" ); document.write( "R=25/.4=62.5 MPH WITH A TAIL WIND. \n" ); document.write( "R=25/.5=50 MPH AGAINST THE WIND. \n" ); document.write( "(62.5-50)/2=12.5/2=6.25 IS THE SPEED OF THE WIND. \n" ); document.write( "PROOF: \n" ); document.write( "62.5-6.25=56.25 MPH FOR THE PLANE. \n" ); document.write( "50+6.25=56.25 DITTO.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |