document.write( "Question 250295: Find the length and width of a rectangle when the length is 5 feet longer than the width. The perimeter of the rectangle is 50 feet.\r
\n" ); document.write( "\n" ); document.write( "Here is what I have:\r
\n" ); document.write( "\n" ); document.write( "2l+2w=P\r
\n" ); document.write( "\n" ); document.write( "2(x+5)+2(x)=50
\n" ); document.write( "2x+10+2x=50
\n" ); document.write( "4x+10=50
\n" ); document.write( "subtract 10 from both sides
\n" ); document.write( "4x=40
\n" ); document.write( "divide then x=10\r
\n" ); document.write( "\n" ); document.write( "Is this correct?
\n" ); document.write( "

Algebra.Com's Answer #182221 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
looks good \n" ); document.write( "
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