document.write( "Question 250295: Find the length and width of a rectangle when the length is 5 feet longer than the width. The perimeter of the rectangle is 50 feet.\r
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document.write( "Here is what I have:\r
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document.write( "2l+2w=P\r
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document.write( "2(x+5)+2(x)=50
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document.write( "2x+10+2x=50
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document.write( "4x+10=50
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document.write( "subtract 10 from both sides
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document.write( "4x=40
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document.write( "divide then x=10\r
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document.write( "Is this correct? \n" );
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Algebra.Com's Answer #182221 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! looks good \n" ); document.write( " |