document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250213>Question 250213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem. How many grams of salt must be added to 40 grams of a 28% salt solution to obtain a 40% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182215 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+.28*40=.40(40+x)<BR>\n" );
document.write( "x+11.2=16+.40x<BR>\n" );
document.write( "x-.40x=16-11.2<BR>\n" );
document.write( ".6x=4.8<BR>\n" );
document.write( "x=4.8/.6<BR>\n" );
document.write( "x=8 grams of salt are used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "8+.28*40=.40(40+8)<BR>\n" );
document.write( "8+11.2=.40*48<BR>\n" );
document.write( "19.2=19.2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );