document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250266>Question 250266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son has a simple problem that I cannot solve.\r<BR>\n" );
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document.write( "A team has a car wash. They charge $3 for cars and $5 per truck. They was 19 vehicles and make a total of $71.00. How many cars and trucks are washed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182184 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A team has a car wash. They charge $3 for cars and $5 per truck. They was 19 vehicles and make a total of $71.00. How many cars and trucks are washed?<BR>\n" );
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document.write( "C + T = 19 (total vehicles)<BR>\n" );
document.write( "3C + 5T = 71 (total charges)<BR>\n" );
document.write( "C + T = 19 --> T = 19-C<BR>\n" );
document.write( "Sub for T in 2nd eqn<BR>\n" );
document.write( "3C + 5*(19-C) = 71<BR>\n" );
document.write( "3C + 95 - 5C = 71<BR>\n" );
document.write( "-2C = -24<BR>\n" );
document.write( "C = 12<BR>\n" );
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document.write( "T = 7<BR>\n" );
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