document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250242>Question 250242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with how to find the equation of the line. <BR>\n" );
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document.write( "Find the equation of the line parallel to 2x+4y=9 and passing through the point (6,-2).\r<BR>\n" );
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document.write( "If someone could walk me through the steps on how to find the answer i would really appreciate it i have a final in two days! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182170 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> convert the equation to slope-intercept form.\r<BR>\n" );
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document.write( "the slope-intercept form of a straight line is y = mx + b where m is the slope and b is the y-intercept.\r<BR>\n" );
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document.write( "2x + 4y = 9 is the equation.\r<BR>\n" );
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document.write( "subtract 4x from both sides of the equation to get:\r<BR>\n" );
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document.write( "4y = -2x + 9\r<BR>\n" );
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document.write( "divide both sides of the equation by 4 to get:\r<BR>\n" );
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document.write( "y = (-2/4)x + (9/4)\r<BR>\n" );
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document.write( "that's the slope intercept of the line.\r<BR>\n" );
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document.write( "the slope is (-2/4) which is the same as (-1/2).\r<BR>\n" );
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document.write( "the equation becomes:\r<BR>\n" );
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document.write( "y = (-1/2)x + (9/4)\r<BR>\n" );
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document.write( "the line parallel to this line will have the same slope.\r<BR>\n" );
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document.write( "the equation for that line starts out as:\r<BR>\n" );
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document.write( "y = (-1/2)x + b\r<BR>\n" );
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document.write( "take your point of (x,y) = (6,-2) and substitute for x and y in this equation to get:\r<BR>\n" );
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document.write( "-2 = (-1/2)*6 + b\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "-2 = -3 + b\r<BR>\n" );
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document.write( "add 3 to both sides of this equation to get:\r<BR>\n" );
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document.write( "-2 + 3 = b\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "1 = b\r<BR>\n" );
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document.write( "equation of line parallel to your line is:\r<BR>\n" );
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document.write( "y = (-1/2)x + 1\r<BR>\n" );
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document.write( "you have 2 equations that are parallel to each other.\r<BR>\n" );
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document.write( "those equations are:\r<BR>\n" );
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document.write( "y = (-1/2)x + (9/4) and y = (-1/2)x + 1\r<BR>\n" );
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document.write( "graph of the equations of these lines is shown below:\r<BR>\n" );
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document.write( "you can see that the equation of y = (-1/2)x + (9/4) crosses the y-axis at about y = 2.25 which is where it would cross when x = 0.\r<BR>\n" );
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document.write( "you can see that the equation of y = (-1/2)x + 1 crosses the y-axis at about y = 1 which is where it would cross when x = 0.\r<BR>\n" );
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document.write( "you can see that the equation of y = (-1/2)x + 1 goes through the point (x,y) = (6,-2).\r<BR>\n" );
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document.write( " </SPAN>\n" );
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