document.write( "Question 250118: The volume v of gas varies inversely as the pressure p on it. The volume of a gas is 240cm^3 under a pressure of 23 kg/cm^2 What will be its volume under pressure of 30 kg/cm^2? \n" ); document.write( "
Algebra.Com's Answer #182109 by Theo(13342)\"\" \"About 
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the equation for inverse variation is:\r
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\n" ); document.write( "\n" ); document.write( "y = k/x\r
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\n" ); document.write( "\n" ); document.write( "in your equation, it states that when y = 240, x = 23\r
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\n" ); document.write( "\n" ); document.write( "you plug that into the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "240 = k/23\r
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\n" ); document.write( "\n" ); document.write( "solve for k and you get k = 23 * 240.\r
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\n" ); document.write( "\n" ); document.write( "k is your constant of variation.\r
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\n" ); document.write( "\n" ); document.write( "when x = 30, the equation becomes.\r
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\n" ); document.write( "\n" ); document.write( "v = k/30 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "v = 23 * 240 / 30 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "v = 184\r
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