document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250068>Question 250068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve the linear system given. Express<BR>\n" );
document.write( "    the answer as an ordered pair of the form (x,y)<BR>\n" );
document.write( "    y = x + 2<BR>\n" );
document.write( "    3x + 2y = 9<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182043 by </B><A HREF=/tutors/aboutme.mpl?userid=actuary><B>actuary(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=actuary><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the \"value\" for y from the first equation into the second equation.<BR>\n" );
document.write( "The second equation then becomes 3x+2(x+2)=9\r<BR>\n" );
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document.write( "ASp;ve the after using the DISTRIBUTIVE PROPERTY, the second equation becomes 3x+2x+4=9\r<BR>\n" );
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document.write( "Solve 3x+2x+4=9 for x\r<BR>\n" );
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document.write( "Subtract 4 from each side of the equation\r<BR>\n" );
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document.write( "The equation is now 3x+2x=5\r<BR>\n" );
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document.write( "Combine like terms so 5x=5\r<BR>\n" );
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document.write( "Divide each side of the equation by 5 so x = 1\r<BR>\n" );
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document.write( "To solve the system of equations for the other variable \"y\", replace \"x\" with 1 in he first equation, so y = 1 + 2 = 3.\r<BR>\n" );
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document.write( "So, x = 1 and y = 3.\r<BR>\n" );
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