document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250020>Question 250020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Olga has 5 times as many dimes as nickels.  If she has $3.30, how many of each coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182028 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Olga has 5 times as many dimes as nickels. If she has $3.30, how many of each coin does she have?<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "d = 5n<BR>\n" );
document.write( "5n + 10d = 330 cents<BR>\n" );
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document.write( "Substitute for d and solve for \"n\":<BR>\n" );
document.write( "5n + 10(5n) = 330<BR>\n" );
document.write( "5n + 50n = 330<BR>\n" );
document.write( "55n = 330<BR>\n" );
document.write( "n = 6 (# of nickels)<BR>\n" );
document.write( "d = 5n = 5*6  30 (# of dimes)<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );