document.write( "Question 250018: solve:
\n" ); document.write( "\"log+base+x%5Blog+base+2%28log+base+3+of+9%29%5D=2\"
\n" ); document.write( "Unfortunately I do not know how to put this without all the words. But this is a problem on one of my take home tests. I dont understand how to solve because I get \"3%5E2=9\" for the log in the parentheses but now I don't knwo what to do?
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Algebra.Com's Answer #182020 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
\"log+base+x%5Blog+base+2%28log+base+3+of+9%29%5D=2\"
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\n" ); document.write( "log3(9) = 2 so your problem becomes:
\n" ); document.write( "\"log+base+x%5Blog+base+2%282%29%5D=2\"
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\n" ); document.write( "log2(2) = 1 so your problem becomes:
\n" ); document.write( "logx(1) = 2
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\n" ); document.write( "x^2 = 1
\n" ); document.write( "x^2-1 = 0
\n" ); document.write( "(x-1)(x+1) = 0
\n" ); document.write( "x = 1 or x=-1
\n" ); document.write( "But -1 cannot be the base of a log.
\n" ); document.write( "So x = 1 is the only solution.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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