document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250009>Question 250009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Penny collected some change in preparation for a garage sale.  She collected two more nickles than twice the number of dimes and eight fewer quarters than twice the number of nickles.  If the value of the quarters was $1.60 greater than four times the value of the nickles and dimes together, what was the total value of the change that Penny collected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182016 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the hard part of these coin problems is setting up the equations<BR>\n" );
document.write( "for every variable (unknown) we need another equation<BR>\n" );
document.write( "so if we have 3 unknowns we need 3 equations<BR>\n" );
document.write( "let n= nickels<BR>\n" );
document.write( "q=quarters<BR>\n" );
document.write( "d=dimes<BR>\n" );
document.write( "n=2d+2<BR>\n" );
document.write( "2n-8=q<BR>\n" );
document.write( "25q=160+4(5n+10d)<BR>\n" );
document.write( "let me know what you get\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );