document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31544>Question 31544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write equation in standard form.<BR>\n" );
document.write( "The line through (-2,4)that is perpendicularto the x-axis </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18200 by </B><A HREF=/tutors/aboutme.mpl?userid=InYourEyes><B>InYourEyes(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=InYourEyes><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=InYourEyes><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all you need to find the slope. Since the line is perpendicular to the x-axis there is no slope. Using the formula y-y1=m(x-x1) we can plug in the numbers.\r<BR>\n" );
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document.write( "1st method:\r<BR>\n" );
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document.write( "y-y1=m(x-x1)<BR>\n" );
document.write( "y-4=m(x--2)<BR>\n" );
document.write( "y-4=m(x+2)<BR>\n" );
document.write( "y-4=0(x+2)<BR>\n" );
document.write( "y-4=0<BR>\n" );
document.write( "y=4<BR>\n" );
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document.write( "Or 2nd method:\r<BR>\n" );
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document.write( "standard form: y=mx+b<BR>\n" );
document.write( "               y=0(-2)+4<BR>\n" );
document.write( "               y=4\r<BR>\n" );
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document.write( "Hope i helped :)\r<BR>\n" );
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document.write( "                 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );