document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250004>Question 250004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor 3z^2+14z +8\r<BR>\n" );
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document.write( "I have tried this repeatedly and I keep coming up with an answer that is exactly like the problem<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181998 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are several ways to look at this but the simplest is to factor<BR>\n" );
document.write( "with 3z as the beginning of one of the factors<BR>\n" );
document.write( "we need to come up with 14 and 8 using 3<BR>\n" );
document.write( "what are factors of 8 which can combine with 3 to make 14<BR>\n" );
document.write( "4*2=8 and 3*4+2=14 <BR>\n" );
document.write( "let's try (3z+4)(z+2)<BR>\n" );
document.write( "that gives us 8 but not the 14 but only 10<BR>\n" );
document.write( "let's try (3z+2)(z+4) yes (3*4) +2=14 and 2*4=8\r<BR>\n" );
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