document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249994>Question 249994</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by substitution. Check your solution.\r<BR>\n" );
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document.write( "19.<BR>\n" );
document.write( "a-1.2b=-3<BR>\n" );
document.write( "0.2b+0.6a=12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181982 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a-1.2b=-3<BR>\n" );
document.write( "0.2b+0.6a=12<BR>\n" );
document.write( "we have two linear equation which form lines on a graph with two variables<BR>\n" );
document.write( "we can then solve for the two variables by elimination or substitution.<BR>\n" );
document.write( "we will substitute<BR>\n" );
document.write( "a-1.2b=-3<BR>\n" );
document.write( "add 1.2b to both sides<BR>\n" );
document.write( "a=1.2b-3<BR>\n" );
document.write( "Substitute 1.2b-3 for a in the second equation.\r<BR>\n" );
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document.write( "0.2b+0.6(1.2b-3)=12<BR>\n" );
document.write( "expand and solve for b<BR>\n" );
document.write( ".2b+.6*1.2b-.6*3=12<BR>\n" );
document.write( "add .6*3 to both sides<BR>\n" );
document.write( ".2b+.6*1.2b=.6*3+12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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