document.write( "Question 249888: A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took 3 hours less time. Find the speed going \n" ); document.write( "
Algebra.Com's Answer #181941 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A person traveled 120 miles in one direction. The return trip was accomplished at double the speed and took 3 hours less time. Find the speed going \n" ); document.write( ": \n" ); document.write( "Let s = original speed \n" ); document.write( "then \n" ); document.write( "2s = return speed \n" ); document.write( ": \n" ); document.write( "Write time equation Time = dist/speed \n" ); document.write( ": \n" ); document.write( "original time - return time = 3 hrs \n" ); document.write( " \n" ); document.write( "reduce fraction \n" ); document.write( " \n" ); document.write( "multiply by s \n" ); document.write( "120 - 60 = 3s \n" ); document.write( ": \n" ); document.write( "60 = 3s \n" ); document.write( "s = \n" ); document.write( "s = 20 mph hr is going speed \n" ); document.write( ": \n" ); document.write( ":\ \n" ); document.write( "Check the times \n" ); document.write( "120/20 = 6 hr \n" ); document.write( "120/40 = 3 hr \n" ); document.write( "-------------- \n" ); document.write( "differ = 3 hrs \n" ); document.write( " |