document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249858>Question 249858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A contractor needs 63 square feet of brick to construct a rectangular walkway. The length of the walkway is 2 feet more than the width. What is the perimeter of the walkway </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181917 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A contractor needs 63 square feet of brick to construct a rectangular walkway. The length of the walkway is 2 feet more than the width. What is the perimeter of the walkway<BR>\n" );
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document.write( "Let the width be \"x\"; length = \"x+2\".<BR>\n" );
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document.write( "Area = x(x+2) = 63<BR>\n" );
document.write( "x^2 + 2x - 63 = 0<BR>\n" );
document.write( "(x+9)(x-7) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 7 ft. (width)<BR>\n" );
document.write( "x+2 = 9 ft. (length)<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "P = 2(9+7) = 2(16)<BR>\n" );
document.write( "P = 32 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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