document.write( "Question 249846: During the first part of a canoe trip, Tim covered 60 km at a certain speed. He then traveled 24 km at a speed that was 4 km/h slower. If the total time for the trip was 8 hr, what was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #181909 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! During the first part of a canoe trip, Tim covered 60 km at a certain speed. \n" ); document.write( "He then traveled 24 km at a speed that was 4 km/h slower. \n" ); document.write( "If the total time for the trip was 8 hr, what was the speed on each part of the trip? \n" ); document.write( "-------------- \n" ); document.write( "1st part DATA: \n" ); document.write( "distance = 60 km ; rate = x km/h ; time = d/r = 60/x hrs \n" ); document.write( "--- \n" ); document.write( "2nd part DATA: \n" ); document.write( "distance = 24 km ; rate = x-4 km/h ; time = d/r = 24/(x-4) hrs \n" ); document.write( "------------------- \n" ); document.write( "Equation \n" ); document.write( "time + time = 8 hrs \n" ); document.write( "60/x + 24(x-4) = 8 \n" ); document.write( "Multiply thru by x(x-4) to get: \n" ); document.write( "60(x-4) + 24x = 8x(x-4) \n" ); document.write( "15(x-4) + 6x = 2x(x-4) \n" ); document.write( "15x-60 + 6x = 2x^2-8x \n" ); document.write( "2x^2 - 29x + 60 = 0 \n" ); document.write( "x = [29 +- sqrt(29^2 - 4*2*60)]/4 \n" ); document.write( "x = [29 +- sqrt(361)]/4 \n" ); document.write( "x = [29 +- 19]/4 \n" ); document.write( "x = 12 or x = 5/2 \n" ); document.write( "--- \n" ); document.write( "solution that gives positive results: \n" ); document.write( "x = 12 km/h (speed on the 1st part) \n" ); document.write( "x -4 = 8 km/h (speed on the 2nd part) \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |