document.write( "Question 31523: Solve
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Algebra.Com's Answer #18185 by mukhopadhyay(490)\"\" \"About 
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x^2+4x=6
\n" ); document.write( "=>x^2+4x-6=0
\n" ); document.write( "=>x^2+4x+4-10=0
\n" ); document.write( "=>(x+2)^2=10
\n" ); document.write( "=>(x+2)=sqrt(10) or (x+2)=-sqrt(10)
\n" ); document.write( "=>x=-2+sqrt(10) or x=-2-sqrt(10)\r
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