document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249730>Question 249730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -7x>1/15  would x= 15/7? can someone help? please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181840 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -7x > 1/15\r<BR>\n" );
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document.write( "Divide both sides by -7 and when you divide by a negative number in inequalities, you switch the direction of the  inequality sign:\r<BR>\n" );
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document.write( "SO:\r<BR>\n" );
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document.write( "x < (1/15)/ -7  so to divide fractions you invert and multiple\r<BR>\n" );
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document.write( "x < (1/15)(-1/7)\r<BR>\n" );
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document.write( "x < -1/105 </SPAN>\n" );
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