document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249715>Question 249715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this equation: 1-2x/3 + x/2 = 1<BR>\n" );
document.write( "When I tryed solving this problem I got X = -4. My book says this answer is correct, but when I tryed to plug it back in it wasn't right. Please show me how to plug it in correctly. Thanks!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181833 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK so X = -4\r<BR>\n" );
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document.write( "Then:\r<BR>\n" );
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document.write( "(1-2x)/3  +  x/2  = 1\r<BR>\n" );
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document.write( "(1-2(-4))/3  + -4/2  = 1<BR>\n" );
document.write( "(1-(-8))/3 - 4/2 = 1<BR>\n" );
document.write( "(1+8)/3 - 2 =  1<BR>\n" );
document.write( "9/3  -  2  =1<BR>\n" );
document.write( "3 - 2 = 1\r<BR>\n" );
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document.write( "Be sure to watch your signs on each number and be sure to perform the operations in the proper order\r<BR>\n" );
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document.write( "Hope this helps </SPAN>\n" );
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