document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249695>Question 249695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two liters of 40% acid are mixed with 4 liters of another acid to form a 50% acid solution. What is the strength of the added acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181824 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have  3 liters 25% acid and  5 liters of another acid and want 60% solution what do I do?<BR>\n" );
document.write( "5+3 liters = 8 liters total<BR>\n" );
document.write( ".25(3)+5x=8(.60)<BR>\n" );
document.write( "solve for x<BR>\n" );
document.write( "Do the same (different numbers of course) for your problem\r<BR>\n" );
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