document.write( "Question 249685: The product of two positive consecutive integers is 41 more their sum. Find the intergers. \n" ); document.write( "

Algebra.Com's Answer #181821 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "The key to these is understanding the words. Let's represent x and x+1 as the two positive consecutive integers.
\n" ); document.write( "Now we can set up an equation.
\n" ); document.write( "X(X+1)=X+(X+1)+41 rewrite it as:
\n" ); document.write( "x^2+x=2x+42 Subtract 2x and 42 from both sides and we get:
\n" ); document.write( "x^2-x-42=0 Now we can factor it to:
\n" ); document.write( "(x-7)(x+6)=0 This gives us:
\n" ); document.write( "x=7
\n" ); document.write( "x=-6 Since the numbers are positive x=7 is the answer. Of course the other integer is 8. Plug in 7 to the original equation and it will work out.
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "

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