document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249668>Question 249668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Sally can paint a house in a 4 hours, and John can paint the same house in 6 hours, How long will it take for both of them to paint the house together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181804 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If Sally can paint a house in a 4 hours, and John can paint the same house in 6 hours, How long will it take for both of them to paint the house together?<BR>\n" );
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document.write( "Use product/sum<BR>\n" );
document.write( "= 4*6/(4+6) = 24/10<BR>\n" );
document.write( "= 2.4 hours.<BR>\n" );
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document.write( "The long way:<BR>\n" );
document.write( "S does 1/4 of the house per hour.<BR>\n" );
document.write( "J does 1/6 per hour.<BR>\n" );
document.write( "Together, they do 1/4 + 1/6 per hour = 5/12<BR>\n" );
document.write( "5/12 house per hour --> 12/5 hours per house<BR>\n" );
document.write( "= 2.4 hours.<BR>\n" );
document.write( " </SPAN>\n" );
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