document.write( "Question 4129: One side of a rectangle is 7 cm longer than the other side. The diagonal is 8 cm longer than the shortest side of the rectangle. Find the dimensions of the rectangle. I am stuck and do not know how to solve this problem \n" ); document.write( "
Algebra.Com's Answer #1818 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = first side of the rectangle (width) \n" ); document.write( " x+7 = second side of the rectangle (length) \n" ); document.write( " x+8 = diagonal of the rectangle (hypotenuse of the right triangle)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is a quadratic equation, so set it equal to zero!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor the left side:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " x = 5 or x = -3\r \n" ); document.write( "\n" ); document.write( "Since x is a side of a triangle, it cannot be negative. Therefore reject the x=-3. \r \n" ); document.write( "\n" ); document.write( "If x = 5, then x + 7 = 12, and x + 8 = 13. \r \n" ); document.write( "\n" ); document.write( "The rectangle is 5 by 12 and the diagonal is 13. \n" ); document.write( " |