document.write( "Question 249599: A square mirror has sides measuring 2 ft. less than the sides of a square painting. If the difference between their areas is 32 ft.^2, find the lengths of the sides of the mirror and the painting. \n" ); document.write( "
Algebra.Com's Answer #181763 by checkley77(12844)\"\" \"About 
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X^2=(X+2)^2-32
\n" ); document.write( "X^2=X^2+4X+4-32
\n" ); document.write( "X^2-X^2-4X=-28
\n" ); document.write( "-4X=-28
\n" ); document.write( "X=-28/-4
\n" ); document.write( "X=7 FT. FOR THE SIDES OF THE SQUARE MIRROR.
\n" ); document.write( "7+2=9 FT. FOR THE SIDES OF THE SQUARE PAINTING.
\n" ); document.write( "PROOF:
\n" ); document.write( "7^2=9^2-32
\n" ); document.write( "49=81-32
\n" ); document.write( "49=49
\n" ); document.write( "
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