document.write( "Question 249603: (y+5)(y-1)=27 \n" ); document.write( "

Algebra.Com's Answer #181757 by checkley77(12844) $\"\"$ $\"About$

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(y+5)(y-1)=27
\n" ); document.write( "y^2+5y-y-5-27=0
\n" ); document.write( "y^2+4y-32=0
\n" ); document.write( "(y+8)(y-4)=0
\n" ); document.write( "y+8=0
\n" ); document.write( "y=-8 ans.
\n" ); document.write( "y-4=0
\n" ); document.write( "y=4 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "(-8+5)(-8-1)=27
\n" ); document.write( "-3*-9=27
\n" ); document.write( "27=27
\n" ); document.write( "(4+5)(4-1)=27
\n" ); document.write( "9*3=27
\n" ); document.write( "27=27 \n" ); document.write( "

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