document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249612>Question 249612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me please?<BR>\n" );
document.write( "5/4x+1/8x=9/8+x<BR>\n" );
document.write( "the solution is x=?<BR>\n" );
document.write( "Im not very good at fractions they confuse me any help will be appreciated. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181752 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/4x+1/8x=9/8+x<BR>\n" );
document.write( "5x/4+x/8-x=9/8 combine the x terms by finding a common denominator.<BR>\n" );
document.write( "(5x*2+x-8*x)/8=9/8 combine the x terms.<BR>\n" );
document.write( "(10x+x-8x)/8=9/8 cancel out the denominators & add the x terms.<BR>\n" );
document.write( "3x=9<BR>\n" );
document.write( "x=9/3=3 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "5*3/4+3/8=9/8+3<BR>\n" );
document.write( "15/4+3/8=9/8+24/8<BR>\n" );
document.write( "30/8+3/8=33/8<BR>\n" );
document.write( "33/8=33/8\r<BR>\n" );
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document.write( " </SPAN>\n" );
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