document.write( "Question 249567: factor 125x3 + 64y3 \n" ); document.write( "

Algebra.Com's Answer #181746 by chosenpoint(26) $\"\"$ $\"About$

You can put this solution on YOUR website!
Equations/249567 (2009-12-14 02:59:25): factor 125x3 + 64y3
\r
\n" ); document.write( "\n" ); document.write( "You can use the following formula to factor the sum of 2 cubes:
\r
\n" ); document.write( "\n" ); document.write( "(a^3+b^3)=(a+b)*(a^2–a*b+b^2)
\r
\n" ); document.write( "\n" ); document.write( "In this specific case, a=5x and b=4y
\r
\n" ); document.write( "\n" ); document.write( "Then we can easily substitute these into our formula
\r
\n" ); document.write( "\n" ); document.write( " $\"%285x%2B4y%29%2825x%5E2-5x%2A4y%2B16y%5E2%29\"$
\r
\n" ); document.write( "\n" ); document.write( " $\"%285x%2B4y%29%2825x%5E2-20x%2Ay%2B16y%5E2%29\"$ simplify and final answer
\r
\n" ); document.write( "\n" ); document.write( "As a note, the difference of two cubes can be found using the following formula:
\r
\n" ); document.write( "\n" ); document.write( "(a^3–b^3)=(a–b)*(a^2+ab+b^2)
\r
\n" ); document.write( "\n" ); document.write( "Answer 181746 by chosenpoint(20) on 2009-12-14 04:59:57
\n" ); document.write( "

\n" );