document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249430>Question 249430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd  , find its area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181693 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W<BR>\n" );
document.write( "2L+2W=P<BR>\n" );
document.write( "2(2W)+2W=48<BR>\n" );
document.write( "4W+2W=48<BR>\n" );
document.write( "6W=48<BR>\n" );
document.write( "W=48/6<BR>\n" );
document.write( "W=8 YDS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*8=16 YDS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*16+2*8=48<BR>\n" );
document.write( "32+16=48<BR>\n" );
document.write( "48=48 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );