document.write( "Question 249465: please guide me on how to solve this problem:
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document.write( "the length of a rectangle is 5cm. more than twice the width. the perimeter of the rectangle is 34 cm. find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #181678 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Turn each statement into an equation using the fewest possible unknowns. \n" ); document.write( ". \n" ); document.write( "L = length of the rectangle \n" ); document.write( ". \n" ); document.write( "Length is twice the width plus 5. \n" ); document.write( "L = 2W + 5 \n" ); document.write( ". \n" ); document.write( "P = perimeter of a rectangle. \n" ); document.write( "P = 2L + 2W = 2(L + W) \n" ); document.write( "P = 34 (given) \n" ); document.write( ". \n" ); document.write( "Substituting what we know... \n" ); document.write( "34 = 2(L + W) \n" ); document.write( ". \n" ); document.write( "Divide both sides by 2... \n" ); document.write( "17 = L + W \n" ); document.write( ". \n" ); document.write( "Substituting L = 2W+5... \n" ); document.write( "17 = 2W + 5 + W \n" ); document.write( ". \n" ); document.write( "Collecting terms and subtracting 5 from both sides \n" ); document.write( "12 = 3W \n" ); document.write( "so \n" ); document.write( "3W = 12 \n" ); document.write( ". \n" ); document.write( "Dividing both sides by 3 \n" ); document.write( "W = 4 \n" ); document.write( ". \n" ); document.write( "L = 2W+5 \n" ); document.write( "L = 2(4)+5 \n" ); document.write( "L = 8+5 \n" ); document.write( "L = 13 \n" ); document.write( ". \n" ); document.write( "Checking the perimeter \n" ); document.write( "P = 2(L+W) = 2(13+4) = 2(17) = 34 \n" ); document.write( ". \n" ); document.write( "Checks. \n" ); document.write( " |