document.write( "Question 249444: Mrs. Smith drove at a rate of 45 mph from her home to her sisters house. she spent 1.5 hrs having lunch with her sister. She then drove back home at a rate of 55 mph. The entire trip, including lunch, took 4 hrs. How far does Mrs. Smith live from her sister?
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Algebra.Com's Answer #181677 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=45T THE TRIP TO HER SISTER'S HOME. \n" ); document.write( "D=55(4-T-1.5) THE RETURN TRIP \n" ); document.write( "45T=55(2.5-T) \n" ); document.write( "45T=137.5-55T \n" ); document.write( "45T+55T=137.5 \n" ); document.write( "100T=137.5 \n" ); document.write( "T=137.5/100 \n" ); document.write( "T=1.375 HOURS FOR THE TO TO HER SISTER'S HOUSE. \n" ); document.write( "4-1.5-1.375=1.125HOURS FOR THE RETURN TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "45*1.375=55(4-1.375-1.5) \n" ); document.write( "61.875=55*1.125 \n" ); document.write( "61.875=61.875 \n" ); document.write( " |