document.write( "Question 249444: Mrs. Smith drove at a rate of 45 mph from her home to her sisters house. she spent 1.5 hrs having lunch with her sister. She then drove back home at a rate of 55 mph. The entire trip, including lunch, took 4 hrs. How far does Mrs. Smith live from her sister?
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Algebra.Com's Answer #181676 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The elapsed time is 4 hr of which 2.5 hr was driving time. \n" ); document.write( "The distance formula is d = rt, where d=distance, r=rate, t=time \n" ); document.write( "We assume the distance to her sister's is the same as it is home (or she drives the same path both ways without any detours). \n" ); document.write( ". \n" ); document.write( "We can define the equation for driving to her sister's house: \n" ); document.write( "d = 45(t) \n" ); document.write( ". \n" ); document.write( "Then the equation for driving home from her sister's house is: \n" ); document.write( "d = 55(2.5-t) \n" ); document.write( ". \n" ); document.write( "In this way, we have defined the two unknown times in terms of a single unknown variable 't' and '2.5-t'. \n" ); document.write( ". \n" ); document.write( "Since d = d, we can say: \n" ); document.write( "45t = 55(2.5-t) \n" ); document.write( "45t = 137.5 - 55t \n" ); document.write( ". \n" ); document.write( "Adding 55t to both sides \n" ); document.write( "100t = 137.5 \n" ); document.write( ". \n" ); document.write( "Dividing both sides by 100 \n" ); document.write( "t = 1.375 \n" ); document.write( ". \n" ); document.write( "So the time spend driving to her sister's house at 45 mph = 1.375 hr \n" ); document.write( "The time spend driving home at 55 mph = 2.5 - 1.375 = 1.125 hr \n" ); document.write( ". \n" ); document.write( "How far does she travel at 45 mph? \n" ); document.write( "d = 45 mph * 1.375 hr = 61.875 miles. \n" ); document.write( "How far does she travel at 55 mph? \n" ); document.write( "d = 55 mph * 1.125 hr = 61.875 miles. \n" ); document.write( ". \n" ); document.write( "So we've checked our work and are confident the distance is 61.875 = 61 7/8 miles. \n" ); document.write( ". \n" ); document.write( "We could be asked what her average speed was, too. \n" ); document.write( "Was it simply (45+55)/2? \n" ); document.write( ". \n" ); document.write( "Well, we see that 2d = 2*61.875 = 123.75 miles \n" ); document.write( "And it took 2.5 hr, so \n" ); document.write( "t = d/r = 123.75/2.5 = 49.5. \n" ); document.write( "So her average speed was 49.5. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |