document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249377>Question 249377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 6 feet long and 4 feet wide. if each dimension is increased by the same number of feet, a new rectangle is formed whose area is 39 square feet more then the area of the original rectangele. by how many feet was each dimension increased? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181671 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=6*4=24 FT^2<BR>\n" );
document.write( "39+24=(6+X)(4+X)<BR>\n" );
document.write( "63=24+10X+X^2<BR>\n" );
document.write( "X62+10X+24-63<BR>\n" );
document.write( "X^2+10X-39=0<BR>\n" );
document.write( "(X+13)(X-3)=0<BR>\n" );
document.write( "X-3=0<BR>\n" );
document.write( "X=3 FT. ANS. FOR THE INCREASE IN LENGTH & WIDTH.<BR>\n" );
document.write( "pROOF:<BR>\n" );
document.write( "63=(6+3)(4+3)<BR>\n" );
document.write( "63=9*7<BR>\n" );
document.write( "63=63<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );